Sunday, February 24, 2008

How Long Does Wind Burn Last



Factor Security issue:





Exercises 1.49 & 1.52



AC connector is steel with a normal stress of 60 ksi last and has a uniform section ¼ x ½ inch. Is connected to a support A and BCD element in C through pins 3 / 8 inch. While BCD element is connected to B by a pin 5 / 16 inch. All pins are steel with an ultimate shear stress of 25 ksi and are subject to simple shear. If you want a safety factor of 3.25, find a) the maximum load P that can be applied D . Note that the AC plug is not reinforced around the holes for the pins. The structure is shown in the figure below:








b) Now solve the above problem assuming that the structure has been redesigned to use pins 5 / 16 "in A , B C and no other changes.





Exercises 1.50, 1.51 & 1.53


The steel structure, shown in the following figure, a 6mm diameter pin is used in C and pins in both 10mm B as D :









The ultimate shear is of 150 MPa in all the connections and the normal stress on the connector last BD is 400 MPa. If you want a safety factor of 3, Halle a) the greatest strength P that can be applied in A (note that the connector BD is not reinforced around the holes for the pins). b) Now solve this problem by assuming that the structure has been redesigned to use 12mm pins B and D . No other change has been made. c) Now solve this problem by assuming that the diameters were changed at the pins on B and D to 11.5mm and that no change has been made.




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